Thermal Decomposition of Ammonium Hexafluorovanadate (III)

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In order to establish the conditions for the preparation of pure vanadium trifluoride, VF3, from ammonium hexafluorovanadate (III), (NH4)3VF6, the preparation of (NH4)3VF6 and its thermal decomposition have been studied by means of thermogravimetric analysis, differential thermal analysis, and X-ray diffraction analysis. Ammonium hexafluorovanadate can be prepared by heating a mixture of V2O3 and NH4HF2 in the molar ratio of 1:8–1:12 at 185–250°C in an inert atmosphere. Vanadium trifluoride can be prepared by heating (NH4)3VF6 at 600–700°C in an inert atmosphere. The mechanism of thermal decomposition of (NH4)3VF6 is as follows:<BR>(NH4)3VF6 → α → β → γ → VF3,<BR>in which α is believed to be ammonium pentafluorovanadate (III), (NH4)2VF5, and β has been found to be a nonstoichiometric compound with the chemical formula of (NH4F)1−x·VF3, 0≤x≤∼0.3, which belongs to a tetragonal system. The lattice parameters of ammonium tetrafluorovanadate (III), NH4VF4(NH4F·VF3), oare a=7.58, c=6.36, ca=0.839. The composition of γ is very near to that of VF3 and γ contains a small amount of NH4F (about 0.1–1.5 wt% NH4).

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